d-test.md 发表于 2020-12-07 更新于 2020-12-15 Shoh^\hat{h}h^ iℏ∂∣ψ⟩∂t=H^∣ψ⟩ i \hbar \frac{\partial \ket{\psi}}{\partial t} = \hat{H} \ket{\psi} iℏ∂t∂∣ψ⟩=H^∣ψ⟩ 好耶 pandoc c=±a2+b2∣ϕ⟩ c = \pm\sqrt{a^2 + b^2} \ket{\phi} c=±a2+b2∣ϕ⟩ sin(x)\sin(x)sin(x) https://qq.com Success Header Welcome to Hexo!
